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The greatest elongation of a given inferior planet occurs when this planet's position, in its orbital path around the Sun, is at tangent to the observer on Earth. Since an inferior planet is well within the area of Earth's orbit around the Sun, observation of its elongation should not pose that much a challenge (compared to deep-sky objects, for example).
Mercury is best observed at the first and last quarter, although they are phases of lesser brightness. The first and last quarter phases occur at greatest elongation east and west of the Sun, respectively. At both of these times, Mercury's separation from the Sun ranges anywhere from 17.9° at perihelion to 27.8° at aphelion.
The planets Mercury and Venus will both cross the ecliptic at the same time. August 25, 11,268 AD A simultaneous total solar eclipse and transit of Mercury: February 28, 11,575 AD A simultaneous annular solar eclipse and transit of Mercury. September 17, 13,425 AD A near-simultaneous transit of Venus and Mercury. 13,727 AD Vega becomes the ...
A spacecraft has beamed back some of the best close-up photos ever of Mercury’s north pole. The European and Japanese robotic explorer swooped as close as 183 miles (295 kilometers) above ...
Due to the proximity of Mercury to the Sun, Mercury on average receives an energy flux from the Sun that is about 7 times the solar constant, but may reach nearly 11 times at maximum and about 4.5 times at minimum. The Sun will have an angular diameter of 1.733 to 1.142°.
Mercury retrograde will shake things up four times in 2024. Here's how to effortlessly thrive during the Mercury retrograde madness. A Complete Guide to Every Mercury Retrograde Happening in 2024
Elongation to Sun January 4, 2005 07:04:06 Venus 7°27' south of Pluto 20.8° West January 5, 2005 00:58:49 Mercury 6°59' south of Pluto 21.6° West January 14, 2005 00:40:51 Mercury 21' south of Venus 18.5° West January 29, 2005 07:05:35 Mars 8°15' south of Pluto 45,5° West February 8, 2005 01:29:22 Mercury 2°04' south of Neptune 4.2° West
For example, to view the eccentricity of the planet Mercury (e = 0.2056), one must simply calculate the inverse sine to find the projection angle of 11.86 degrees. Then, tilting any circular object by that angle, the apparent ellipse of that object projected to the viewer's eye will be of the same eccentricity.